SOLUTION: 1. (2x^2 + x - 3)/9 times (x + 1)^2/(2x^2 + 5x + 3)
2. 1/(25 - y^2) divided by (6 - 3y)/y^2 - 7y + 10)
3. abc/(a^2 - 3a - 10) divided by a^2/(a^2 - 25) times (4 - a^2/9b^2 -
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Question 256883: 1. (2x^2 + x - 3)/9 times (x + 1)^2/(2x^2 + 5x + 3)
2. 1/(25 - y^2) divided by (6 - 3y)/y^2 - 7y + 10)
3. abc/(a^2 - 3a - 10) divided by a^2/(a^2 - 25) times (4 - a^2/9b^2 - 4 divided by (abc + 5bc)/(3ab - 2a)
4. (n^2 + 5n + 6)/(n^2 + 7n + 12 times (n^2 + 9n + 20/(n^2 + 11n + 30)
Found 2 solutions by richwmiller, drk:
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
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Answer by drk(1908) (Show Source): You can put this solution on YOUR website!
1. (2x^2 + x - 3)/9 times (x + 1)^2/(2x^2 + 5x + 3)
step 1 - factor all possible polynomials as
*
step 2 - cancel where needed as
which is simplified as
--
2. 1/(25 - y^2) divided by (6 - 3y)/y^2 - 7y + 10)
step 1 - factor all possible polynomials as
/
step 2 - multiply by reciprocal to get
* *
--
3. abc/(a^2 - 3a - 10) divided by a^2/(a^2 - 25) times (4 - a^2/9b^2 - 4 divided by (abc + 5bc)/(3ab - 2a)
step 1 - factor all possible polynomials
/ * /
which becomes
* * *
step 2 - reduce as needed to get
/
--
4. (n^2 + 5n + 6)/(n^2 + 7n + 12 times (n^2 + 9n + 20/(n^2 + 11n + 30)
step 1 -factor all possible polynomials to get
*
this reduces nicely to
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