SOLUTION: how do you solve for x in this problem: .30 = 7-50+45(1+x)^-.25

Algebra.Com
Question 232755: how do you solve for x in this problem: .30 = 7-50+45(1+x)^-.25
Found 2 solutions by jsmallt9, Alan3354:
Answer by jsmallt9(3758)   (Show Source): You can put this solution on YOUR website!

Solving for x means that, at the end, we want an equation that looks like:
x = some-expression
or
some-expression = x
So we want to get x by itself. Note that as we go through the following steps expression on the same side of the equation as x get smaller and smaller. We'll start with simplifying 7-50:

Now we'll add 43 to both sides:

Divide both sides by 45:

The next part of the right side we want to remove is the exponent. There's a couple of ways to proceed:

Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
.30 = 7-50+45(1+x)^-.25
---------------
0.3 = -43 + 45/(1+x)^0.25
43.3 = 45/(1+x)^0.25
(1+x)^0.25 = 45/43.3
1+x = (45/43.3)^4
x = (45/43.3)^4 + 1
x = ~ 2.166537

RELATED QUESTIONS

How do I solve for N in the following equation? $45 = [N($50) + $25]/(N + 1) Thank... (answered by josgarithmetic,richwmiller)
how do you solve for y in this problem... (answered by josgarithmetic)
Solve for x: x + 25 = 45 i do not get how to do... (answered by rothauserc)
How do you solve this equation? X 5 50 ___ - ___ =_____ x-5 x+5 x square (answered by jayanthi)
how do you solve this problem? : solve for x: 6^3x =... (answered by lwsshak3)
how do you solve this problem? x+x _ _ 5... (answered by jim_thompson5910,stanbon)
how do you solve this problem:... (answered by jim_thompson5910)
how do i solve for x in this problem: 3=1/4 square root of 3x +... (answered by edjones)
how do you solve this problem... (answered by tran3209)