SOLUTION: 2r^-5 y^3 over n^2 divided by r^2 y^5 over 2n I have no clue where to start with this. Thank you for your help

Question 187424This question is from textbook Algebra 1
: 2r^-5 y^3 over n^2 divided by r^2 y^5 over 2n

I have no clue where to start with this. Thank you for your help
This question is from textbook Algebra 1

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
2r^-5 y^3 over n^2 divided by r^2 y^5 over 2n
---------------------------------------------
[(2y^3/r^5)/n^2] / [r^2y^5/2n]
= [(2n^2y^3/r^5] * [2n/r^2y^5]
Cancel factors that are common to any numerator and a denominator,
such as y^3
= [(2n^2/r^5] * [2n/r^2y^2]
= [4n^3] / [r^7y^2]
==================================
Cheers,
Stan H.
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