SOLUTION: (c^-1)^-12(c^-5)^6/(c^-4)^0(c^3)^-3 answer 1/c^9 How do I get there? I am so lost! please help

Question 150455: (c^-1)^-12(c^-5)^6/(c^-4)^0(c^3)^-3
answer 1/c^9
How do I get there? I am so lost! please help

Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Let's break this problem down.

First let's simplify the numerator

Start with the first term in the numerator

Multiply the exponents using the identity

Multiply -1 and -12 to get 12

So simplifies to

----------------------------------

Move onto the second term in the numerator

Multiply the exponents using the identity

Multiply -5 and 6 to get -30

So simplifies to

=========================================================

So the expression now becomes

=========================================================

Now let's simplify the denominator

Start with the first term in the denominator

Multiply the exponents using the identity

Multiply -4 and 0 to get 0

Raise c to the zeroth power to get 1

So simplifies to

-------------

Move onto the second term in the denominator

Multiply the exponents using the identity

Multiply 3 and -3 to get -9

So simplifies to

========================================

So after simplification, we go from to

Start with the given expression.

Multiply 1 and to get

Multiply the terms in the numerator by adding the exponents.

Add 12 to -30 to get -18

Divide the terms by subtracting the exponents.

Rewrite to get

Add -18 to 9 to get -9

Rewrite as to make the exponent positive.

========================================================

Answer:

So simplifies to
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