SOLUTION: I'm soooo confused, I'm in the 7th grade and my math teacher isn't explaining algebra in a way I understand. I understand and can figure out that 1/3(s+6)=3 and that 's' is -3 (I t

Question 139203: I'm soooo confused, I'm in the 7th grade and my math teacher isn't explaining algebra in a way I understand. I understand and can figure out that 1/3(s+6)=3 and that 's' is -3 (I think) but what I don't get is 2/3(x18)=-6. I DON'T GET IT!!! What's the answer and how do I get it? Please help!My teacher tried to help with a diffrent problem, 2/3x=12 with 'x'being 18 she wrote out the way to solve it but it still dosn't make any sense to me
Found 2 solutions by stanbon, ankor@dixie-net.com:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
I understand and can figure out that 1/3(s+6)=3 and that 's' is -3 (I think) but what I don't get is 2/3(x18)=-6. I DON'T GET IT!!! What's the answer and how do I get it? Please help!My teacher tried to help with a diffrent problem, 2/3x=12 with 'x'being 18.
-----------------
Let's look at the three equations you mentioned:
1st: (1/3)(x+6) = 3
Multiply both sides by 3 to get-------
x+6 = 9
Subtract 6 from both sides to get-----
x = 3
================================
2nd: (2/3)(x18)= -6
Multiply both sides by (3/2) to get---------
x18 = -9
Divide both sides by 18 to get------------
x = -1/2
-------------------
(2/3)x = 12
Multiply both sides by (3/2) to get:
x = 18
------------------
cheers,
Stan H.
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
I'm soooo confused, I'm in the 7th grade and my math teacher isn't explaining algebra in a way I understand. I understand and can figure out that 1/3(s+6)=3 and that 's' is -3 (I think) but what I don't get is 2/3(x18)=-6. I DON'T GET IT!!! What's the answer and how do I get it? Please help!My teacher tried to help with a diffrent problem, 2/3x=12 with 'x'being 18 she wrote out the way to solve it but it still dosn't make any sense to me:
:
I am not sure that I understand everything you said here, however;
let's go over the problem that you think you know, step-by-step:
(s+6) = 3
:
Get rid of the denominator multiply both sides by 3:
3*(s+6) = 3*3
Cancel the denominator, multiply on the right, and you have;
1(s+6) = 9
:
Multiply both terms inside the brackets by 1:
s + 6 = 9
:
Subtract 6 from both sides and you have (we want s by itself on the left):
s = 9 - 6
:
s = +3
:
Confirm the solution is correct by substituting 3 for s
(3+6) = 3
*9 = 3
:
:
The next problem is;
x = 12
Get rid of the denominator by multiplying both sides by 3:
3*x = 3*12
Cancel the denominator, multiply 12 by 3;
2x = 36
:
divide both sides by 2:
x =
x = 18
:
prove that it is correct by substituting the solution for x
*18 = 12
:
:
did this help you? do you have any questions?
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