SOLUTION: Please can you help me, I tried figuring it out but no luck.
4x^4= 13x^2-9
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Question 123145This question is from textbook College Algebra Essentials
: Please can you help me, I tried figuring it out but no luck.
4x^4= 13x^2-9
This question is from textbook College Algebra Essentials
Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
4x^4-13x^2+9=0
factoring __ (4x^2-9)(x^2-1)=0 __ both factors are difference of two squares
factoring (again) __ (2x+3)(2x-3)(x+1)(x-1)=0
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