SOLUTION: If 800g of a radioactive substance are present initially and 8 years later only 450g remain, how much of the substance will be present after 16 years?
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Question 1183275: If 800g of a radioactive substance are present initially and 8 years later only 450g remain, how much of the substance will be present after 16 years?
Found 2 solutions by greenestamps, ikleyn:
Answer by greenestamps(13200) (Show Source): You can put this solution on YOUR website!
Over the space of 8 years, the amount remaining decreases by a factor of 450/800 = 9/16.
After another 8 years, the amount will again decrease by the same factor.
ANSWER: (9/16)*450 = 253 1/8
Since radioactive decay is a statistical process, it should be okay to round the answer to 253g.
Answer by ikleyn(52794) (Show Source): You can put this solution on YOUR website!
.
On radioactive decay, see the lesson
- Radioactive decay problems
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