SOLUTION: We have tried and tried to find the answer, but can't seem to figure out when to use the multipicative inverse to solve it. The problem is: 2^2x = 8^(x-1) Hope you can help. Tha

Question 101910: We have tried and tried to find the answer, but can't seem to figure out when to use the multipicative inverse to solve it. The problem is:
2^2x = 8^(x-1) Hope you can help. Thanks!
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
The problem is:
2^2x = 8^(x-1)
------------------
Write both sides to the base 2 as follows:
2^(2x) = (2^3)^(x-1)
2^2x = 2^[3x-3]
Since the bases are the same the exponents are equal.
2x = 3x-3
-x = -3
x = 3
===========
Cheers,
Stan H.
RELATED QUESTIONS
I cant seem to figure out the answer to this question and I have tried and tried to solve (answered by Alan3354)

Please can you help me with this equation, I have tried but can't figure it out. The... (answered by fners)

Two contestants run a 440-yard course. The first wins by 4 seconds when given a head... (answered by MathTherapy)

I need to figure the following out. I have tried it but I get confused, I can't seem to... (answered by Earlsdon)

How much coffee costing $6.00 per pound should be mixed with 3 pounds of coffee costing... (answered by bucky)

I can't seem to figure out 10/7 - 6/x I seem to have tried... (answered by Alan3354)

I have tried this problem and cannot seem to figure it out! It is:... (answered by lwsshak3)

I posted this earlier but I cannot seem to get the answer can someone please help out... (answered by stanbon)

"Use the Addition Property and/or Multiplication Properties to find a and b. If -3 < x < (answered by mangopeeler07)