My question is based around 'Solving Systems of Equations by the Substitution Method'.
I understand the concept of plugging in the x or y value into the one or the other equation but for some (very frustrating) reason whenever I follow these steps I don't come out with the right answer. I will list two below.
1. 4x-y=-1
2x+4y=13
I chose to take the top equation (4x-y=-1) and make that into -y=-4-1 and change that further by dividing by -y to get y=-4x+1. MY FIRST QUESTION is why did I have to change -1 to +1?
I then tried to plug y=-4x+1 into the 2x+4y=13 but I never get the right answer! Help?
2. x-3y=-11
6x-y=2
please help?
4x - y = - 1 -------- eq (i)
2x + 4y = 13 -------- eq (ii)
For the 1st equation, all you have to do is add y to both sides to get:
4x = - 1 + y
Then add 1 to get: 4x + 1 = y
Now we have: y = 4x + 1 ------- eq (i)
2x + 4y = 13 --------- eq (ii)
2x + 4(4x + 1) = 13 ------- Substituting 4x + 1 for y in eq (ii)
2x + 16x + 4 = 13
18x = 9
x = , or
-------- Substituting for x in eq (i)
y = 2 + 1, or
Follow the same steps and you should be able to do no. 2