Tutors Answer Your Questions about Exponents-negative-and-fractional (FREE)
Question 750612: Hello, I am trying to solve a algebra math problem but not sure what the next step to take is. Please help me understand and help solve this problem, thank you.
Question: Simplify. Not to use negative exponents in answer.
(3m^ -5n)^4
___________ * (-4mn^3)^2
(9m^2n^ -2)
For this problem I start off by making the negative exponents positive by placing 1 to go over the ones that have negative exponents.
1
__
3m^5 and but after I get the negative exponents to be positive, I am not sure what the next step is and what to do with (-4mn^3)^2 Answer by Edwin McCravy(8909) (Show Source):
Question 749956: Please help!
1/3y ^-3 Answer by unlockmath(1603) (Show Source):
You can put this solution on YOUR website!Hello,
Math people don't like negative exponents, so to get rid of such place it in the Denominator as:
1/3/(y^3)
This can be rewritten as:
1/(3y^2)
(Note: I'm assuming the original problem was 1/3 times y^-3)
RJ
Question 749470: What is the simplest form of the given expression?
2.9X10^7 / 5.8X10^10 Answer by josgarithmetic(1540) (Show Source):
You can put this solution on YOUR website!Your result should fit the form, U.Tx10^p, where U is the digit in the ones place, T is the digit in the tenths place, and p is the exponent, an integer. The "x" is used only as a multiplication symbol.
2.9X10^7 / 5.8X10^10
You mean
= 
=
The system is not rendering everything properly. The highlighted number should show 5.0 x 10^(-4), because we should keep two significant figures for the available accuracy, according to the accuracy available for the starting numbers.
Question 716654: (a^3/m)^-4 Answer by kekegeter (57) (Show Source):
Question 722547: (5y^4)^-3(2y^-2)3 Answer by kekegeter (57) (Show Source):
Question 738140: 1.) 3x+12=15/x
2.) 3/x-3=5/x^2-9-2/x+3 Answer by kekegeter (57) (Show Source):
Question 745593: 2/3-4/5-(-11/15)+7/10-5/2 Answer by kekegeter (57) (Show Source):
Question 745595: -9.6+7.4-(-3.9)-(-11) Answer by kekegeter (57) (Show Source):
Question 746098: please help me with this question, and i dont know if this problem is under the correct category sorry. "simplify each expression below. your answer should contain no parentheses and no negative exponents" 5t^-3 (five t negative cube) Answer by josmiceli(9697) (Show Source):
Question 745994: the lowest point in Aftica is lake Assal, which is 512ft below sea level. The lowest point in South Africa is the valdes Peninsula, which is 131 ft below sea level. how much lower is Lake Assal than Valdes Peninsula? Answer by checkley79(3050) (Show Source):
Question 745588: -4/5-(-4/5)
Answer by tommyt3rd(608) (Show Source):
Question 745565: We let T = the total change in the level of the lake. Then the problem translate to a sum. T= -5/8 + (-1/6) Answer by stanbon(57387) (Show Source):
Question 745461: Please help me solve this equation:
a^-11 / a^-8
That is: a to the power of negative 11 divide by a to the power of negative 8.
Thank you. Answer by stanbon(57387) (Show Source):
Question 745273: I don't understand how to solve:
10x^3 +y^2÷2 -x^3÷3 +y^2÷4 -2x^2÷3
I would really appreciate if you could show me the steps to solving this equation by tonight.
The given answer that was provided to me was 30÷3x^3 -x^3÷3
Thank you. Answer by rothauserc(210) (Show Source):
You can put this solution on YOUR website!we are asked to solve
10x^3 +y^2÷2 -x^3÷3 +y^2÷4 -2x^2÷3
group like terms together and we have
10x^3 - X^3/3 -2x^2/3 +y^2/2 + y^2/4
30x^3/3 - x^3/3 -2x^2/3 +2y^2/4 + y^2/4
29x^3/3 - 2x^2/3 +3y^2/4
Question 743762: 1-2ab-(a²+b²) Answer by Ed Parker(21) (Show Source):
You can put this solution on YOUR website!
1 - 2ab - (a² + b²)
Remove the parentheses:
1 - 2ab - a² - b²
Enclose the last three terms in a parentheses preceded by a minus:
1 - (2ab + a² + b²)
Swap the first two terms inside the parentheses:
1 - (a² + 2ab + b²)
Factor the trinomial in the parentheses:
1 - (a + b)(a + b)
Write that as a square:
1 - (a + b)²
Factor as the difference of two squares:
1² - (a + b)²
[1 - (a + b)][1 + (a + b)]
Remove the inner parentheses:
[1 - a - b][1 + a + b]
Change the brackets to parentheses:
(1 - a - b)(1 + a + b)
Edwin
Question 740051: factor 12s^3-21s^2+12s Answer by MathLover1(6638) (Show Source):
Question 739690: 18x^3y^2/30x^4y^5 simplify Answer by checkley79(3050) (Show Source):
Question 739691: simplify 12x/3x+9 Answer by checkley79(3050) (Show Source):
Question 739694: simplify 15a+9ab/6a Answer by checkley79(3050) (Show Source):
Question 739696: simplify Answer by josgarithmetic(1540) (Show Source):
Question 739693: simplify 3x^2+6x/3x^2+9x Answer by josh's girl(6) (Show Source):
Question 738449: Write answer in scientific notation:
(4.1*10^2)(3*10^-5)
I did: (4.1*3)*(10^2*10^5)=(4.1*3)*10^7=12.3x10^7 as my answer
Here is where I am confused, since the number is greater than 10 should it still be written in scientific notation? Is my answer correct? Thanks
I then reworked the problem as 0.0123 or 1.23x10^-2, a previous answerer said the exp was ^2, which is correct?
Answer by Hchu243(2) (Show Source):
You can put this solution on YOUR website!You're first answer was correct, except because your answer was greater than 10, it should be written as 1.23*10^8. You move the decimal point over one and increase the decimal one; in scientific notation, you can only have 1 integer before the decimal.
Question 738395: Write answer in scientific notation:
(4.1*10^2)(3*10^-5)
I did: (4.1*3)*(10^2*10^5)=(4.1*3)*10^7=12.3x10^7 as my answer
Here is where I am confused, since the number is greater than 10 should it still be written in scientific notation? Is my answer correct? Thanks Answer by checkley79(3050) (Show Source):
Question 738378: A-(9b-13b)=
A=12, b=-2
Found 2 solutions by rfer, jim_thompson5910: Answer by rfer(12670) (Show Source): Answer by jim_thompson5910(28598) (Show Source):
You can put this solution on YOUR website!Replace A with 12 and b with -2, then evaluate like this
A-(9b-13b)
12-(9*(-2)-13*(-2))
12-(-18+26)
12-(8)
12-8
4
So A-(9b-13b) = 4 when A = 12 and b = -2
Question 737996: (2/3)^4
I have to write it in simplest form, so I simplified it to- 2^4/3^4, but do I need to simplify it so it doesn't have the exponents in it anymore? Answer by lynnlo(4164) (Show Source):
Question 737694: 1.) 3x+12=15/x
2.) 3/x-3=5/x^2-9-2/x+3 Answer by josgarithmetic(1540) (Show Source):
You can put this solution on YOUR website!1.) 3x+12=15/x
Clear the fractions. Multiply left and right sides by x. You now have a quadratic equation, easier to solve. Just a little rearranging is needed first.

divide b.s. by 3
 and you can finish this one, but check answers against the original equation in case one answer is "extraneous".
2.) 3/x-3=5/x^2-9-2/x+3
That is likely expressed incorrectly so what you want is not clear. If it IS written correctly, then the lowest or simplest denominator is x^2, and you would multiply the left side and right side by x^2 which would clear the fractions.

Which use of quadratic formula will give 
and that will simplify into  or  . Complex solutions.
Question 737304: (7x – 0.6) – (-2x2 + 4x – 8) Answer by rfer(12670) (Show Source):
Question 737308: Use special product formula: (7a + 2)2 Answer by MathLover1(6638) (Show Source):
Question 737306: (12x^2 - 6x + 3)/3 Answer by stanbon(57387) (Show Source):
Question 737305: (-4p2 – 3p – 2) + (-p2 – 4)
Answer by stanbon(57387) (Show Source):
Question 734322: How to begin in a problem like this, 4x+3/15 - 2x-3/9 = 6x+4/6 - x . Thank you for any help! Answer by stanbon(57387) (Show Source):
You can put this solution on YOUR website!How to begin in a problem like this,
----------------------
4x+3/15 - 2x-3/9 = 6x+4/6 - x
Multiply thru by 90 to get:
-----
6*(4x+3) - 10(2x-3) = 15(6x+4) - 90x
-----
24x + 18 -20x + 30 = 90x + 60 - 90x
-----
4x + 48 = 60
4x = 12
x = 3
================
Cheers,
Stan H.
================
Question 734313: 1 1/6 + x/8 = 7/24 Not sure what to do once I turn the mixed fraction to an improper one. any help would be appreciated. thanks. Answer by rfer(12670) (Show Source):
Question 734233: x^-2 multiplied by x^-3 Answer by MathLover1(6638) (Show Source):
Question 732491: evaluete 25^3/2 Answer by lynnlo(4164) (Show Source):
Question 731208: What is 4 divided c times c to the negative fifth power.. Answer by MathLover1(6638) (Show Source):
Question 730794: what is equal to (6^-7)^3?
A. (1/6)^21
B. (-1/6)^-21
C. (1/6)^-21
D. (-1/6)^21 Answer by lynnlo(4164) (Show Source):
Question 729748: there are 2. got them wrong on a test and cant come up with the teachers answer
1) solve for X: a/bx-c=0 . I get x=cb/a
2) subtract: 3x+1/x2(squared)-9 minus 2x-2/x2(squared -9. my answer x-1/x2(squared -9 Found 2 solutions by MathLover1, Alan3354: Answer by MathLover1(6638) (Show Source): Answer by Alan3354(30993) (Show Source):
You can put this solution on YOUR website!1) solve for X: a/bx-c=0 . I get x=cb/a
Is it (a/b)x ?
Or a/(bx) ?
2) subtract: 3x+1/x2(squared)-9 minus 2x-2/x2(squared -9. my answer x-1/x2(squared -9
Use ^ (Shift ^) for exponents.
Question 727745: Please help me solve this equation: a^2 over b^2 divided by a over b^3 Answer by stanbon(57387) (Show Source):
You can put this solution on YOUR website!a^2 over b^2 divided by a over b^3
-----
(a^2/b^2) / (a/b^3)
---
Invert the denominator and multiply:
= (a^2/b^2) * (b^3/a)
-----
= (a^2/a)(b^3/b^2)
Cancel where you can:
----
= ab
===========
Cheers,
Stan H.
Question 726524: 3(x-3)=3
7
3 over 7 Answer by lynnlo(4164) (Show Source):
Question 725301: Simplify: (3x + 4y) - (2x - 5y) Answer by checkley79(3050) (Show Source):
Question 725217: 5\2x-3-1\x plus 5 Answer by stanbon(57387) (Show Source):
Question 724815: How do I solve this problem? I'm trying to help my daughter and I'm lost.
2a to the -5 power over b to the -6 power.
She is trying to simplify this problem. Found 2 solutions by mananth, KMST: Answer by mananth(12270) (Show Source): Answer by KMST(1874) (Show Source):
You can put this solution on YOUR website!I would not call it simplifying, but we can transform it into an expression with positive exponents:

Any powers with negative exponents can cross the fraction line to make their exponents turn positive.
EXPLANATION:
 by definition, and  too
 <--->  <---> 
In baby steps that are not usually spelled out:
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