Questions on Algebra: Exponent and logarithm as functions of power answered by real tutors!

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 Algebra: Exponent and logarithm as functions of power Solvers Lessons Answers archive Quiz In Depth

 Question 574650: Ok, so I just want to know the method of finding the base of a logarithm. I am given a picture of a graph; two points of a function, (3,5) and (5,9); and the asymptote: x=2 . I see that there are 6 variables for me to find, and that I am given 5 numbers to "plug" in. I see how the graph points (3,5) and (5,9) fit into the equation y=alog↓b(x-h)+k, but I don't understand how to put the asymptote into the equation or how to find base b. Is there a specific way to find base b of a graph using these? Click here to see answer by KMST(1868)

 Question 575203: How do you solve for E in the following equation? 9=0.67log(0.37E)+1.46 Click here to see answer by josmiceli(9681)

 Question 575448: what is the value of x? please explain by showing work 2 - Log 3x = Log (x/12) + 2 Click here to see answer by solver91311(16897)

 Question 576749: The half-life of a radioactive substance is the time it takes for half of the substance to decay. The half-life if carbon-14 is 5700 years. A.) write a exponential function to model the decay of a 240-my sample. B.) explain what each value in the function model represents. C.) to the nearest hundredth, find the amount of carbon-14 remaining after 2353 years. Explain how you found this amount. Click here to see answer by ankor@dixie-net.com(15652)

 Question 577833: (x+7)^(2/3)=9 I got 20 as one solution for x and I know it's correct, but I'm supposed to find a second one as well. please help ^(2/3) means *to the power of 2/3* in case that was confusing Click here to see answer by Alan3354(30993)

 Question 578260: A business has a \$20,000 profit in 1990. The profit increased by 20% per year for the next 10 years. Write an exponential growth model. Click here to see answer by dfrazzetto(277)

 Question 578449: Please help me solve the below algebra problem. The problem should read x to the 3/2 power=125... I tried to set up the problem the best way I could. Thank you :) x^3/2=125 Click here to see answer by KMST(1868)

 Question 579079: 64 to the 7/9 power divided by 4 to the 3/4 power. Having trouble showing answer of 8.98. Click here to see answer by jim_thompson5910(28595)

 Question 579128: i need help in math the section were in is applications of logarithms. the problem is x to the power of 2 over 7 =24 Click here to see answer by dfrazzetto(277)

 Question 578986: how would you solve 3^(x+4) = 6^(2x-5)? I don't know where to start... thank you so much! Click here to see answer by nerdybill(6959)

 Question 579649: Use log(4)3 approxiatimately equals 0.7925 to approximate the value of the expression log(4)384. I cannot come up with any factors that give me 4 or 3 evenly. Click here to see answer by richard1234(5390)

 Question 579984: I submitted a question earlier but I have figured it out. The question was 36 to the 5X - 2 power = 1/6 to the 11- x power. I no longer need the solution as I got the answer which is -5/3. Thank you. Click here to see answer by dfrazzetto(277)

 Question 580940: In terms of logarithms, or correct to at least four decimal places x= 19^x=10. 18e^x=11 x= In(x)=4 x= Click here to see answer by Alan3354(30993)

 Question 581664: The question is: log x^3 - 2log 1/x - 1= 0 What I tried: 3log x- (-2log x) - 1= 0 3log x + 2 log x - 1= 0 5 log x- 1 = 0 5 log x = 1 log x = 1/5 x= 10^1/5 or 3log x- (-2log x) - 1= 0 3log x + 2 log x - 1= 0 5 log x- 1 = 0 5 log x = 1 log x^5 = 1 x^1=5 x=5 I'm still confused with this kind of questions. Thanks in advance ^0^! Click here to see answer by nerdybill(6959)

 Question 581749: The question is: log(base x)2 + log(base2)x= -2 What I did: log(base x)2 + log(base2)x= -2 log(base x)2+ 1/log(base x)2= -2 (log (base x)2)^2 + 1= -2log(base x)2 Take log(base x)2 as a: a^2 + 1= -2a a^2 + 2a + 1= 0 (a+1)(a+1)=0 a+1=0 a=-1 log(base x)2= -1 x^-1= 2 x= 1/2 I tried doing this, but I'm not sure if I'm right =) Thanks in advance!! Click here to see answer by lwsshak3(6508)

 Question 581754: This is the question: log(base 5) 125^1/2 + log(base 11) 121^1/3= 13/6 What I tried: log(base 5) 125^1/2 + log(base 11) 121^1/3 = 13/6 log(base 5) 5*5^1/2+ log (base11) 121^1/3= 13/6 Yup,unfortunately, I'm stuck at here. Thanks in advance ^0^!! Click here to see answer by nerdybill(6959)

 Question 582434: Hi, I'm having a lot of trouble with a couple of different questions. I did do the homework on this, but I feel like I did not do an example like this. A) (25u^2)^5/2 B) b^2/3b^2/3 / -b^1/3 C) Find the perimeter of the trapezoid. This one they gave us a problem like it, but they never made us set it up fully. So I'm not even sure how to set it up. Sides: 4 square root of 50, 2 square root of 72, 3 square root of 2, & the square root of 50. Click here to see answer by stanbon(57357)

 Question 582895: Solve log5x+log10=0. Round to the nearest hundredth if necessary. This what I have tired: log5(x+2)=0 10^log5(x+2)= 10^0 5x+10=1 I wasn't sure what to do next and if I was doing the problem correctly. Click here to see answer by nerdybill(6959)

 Question 583758: Suppose the population of a country was 200,000,000. If the population grows by 1.5% annually, by how many people will the population increase in the next 6 years? Click here to see answer by Alan3354(30993)

 Question 585113: The value of a piece of equipment has a decay factor of 0.80 per year. After 5 years the equipment is worth \$98,304. What was the original value of the equipment? Click here to see answer by richwmiller(9143)

 Question 585112: The value of a piece of equipment has a decay factor of 0.080 per year. After 5 years, the equipment is worth \$98,304. What was the original value of the equipment? Click here to see answer by Alan3354(30993)

 Question 585321: I know only basic maths. I have a great calculator. Negative exponent - less than 1 How do I solve for V in the equation 11.2 = 276V^-0.65? i.e. 276V to the power of minus .65. Thanks. Click here to see answer by Alan3354(30993)

 Question 585645: Okay so for a car project I have this problem and I need to find out how long it would take for me to pay for the car to pay less than 125% of what it is worth.- A=P(1+r/12)^t. A= amount of money total i paid for the car,P= amount of loan i needed) r= interest rate and t= length of loan(in months) For my particular case, I have: A= 26641.12, P= 21000, r= .0349 (3.49%), and t= 48. I know I have to use logarithms to get T down to find the time, but I'm stuck Click here to see answer by ankor@dixie-net.com(15652)

 Question 586071: Translate the given logarithmic statement into an equivalent exponential statement. log(a+c)= d Click here to see answer by jim_thompson5910(28595)

 Question 586510: how do you solve 2 log x = -1 Click here to see answer by Alan3354(30993)

 Question 586189: 4e^x+2=32 ln(5x-3)^1/3=2 2x^(3x-2)+4=16 2e^(x-2)=e^x+7 1/3lnx+ln2-ln3=3 ln(x+2)-ln4=3 Hello. Thank you for your time. I have a test and Im practicing on these problems, but I keep getting something wrong. Can you work them out please? Thank you sooo much!!! =) Click here to see answer by ankor@dixie-net.com(15652)

 Question 586750: how do i solve: log base 2 8 (log2 8) Click here to see answer by Alan3354(30993)

 Question 587053: I would like to know how to figure out if a function is NEITHER exponential growth or decay! For example, is the following function neither!?: (please explain why or why not) y=3*((e^-1)^x)-8 Thanks in advance! :-) Click here to see answer by stanbon(57357)

 Question 587356: which of the following shows log27 9=2/3 correctly written in exponential form? Click here to see answer by Alan3354(30993)

 Question 587461: the population of India is 1.17 billion people and is expected to double in 44 years. the population of CHina is 1.34 billion people and is expected to double in 67 years. if the trends continue, when will the population of inda be the same as China's? round your answer to the nearest tenth of the year. Click here to see answer by stanbon(57357)