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Tutors Answer Your Questions about Exponential-and-logarithmic-functions (FREE)
Question 110268: These 3 problems are from a worksheet, not a textbook, and I so desperately need them solved within the next hour, if possible. I tried and cannot work them out. Thanks!
1.Solve the following exponential equation. Your solution should be accurate to 2 decimal places.
41/(1-1e^7x) = 56
2. Solve the following exponential equation. Your solution should be accurate to 2 decimal places.
5e^-5 + 5 = 7
3. Solve the following logarithmic equation. Your solution should be accurate to 2 decimal places.
ln(x-4) + ln(7) = 4
Thank you very much for your help with this tonight.
Click here to see answer by scott8148(3382)   |
Question 110831: If I want a patio that has 9 times the are by what factor do I have to increase the side?
I think that the answer is 3. I know that if I increase x by a factor of t, then f is increasedc by a factor of t^k. It is doing is backwards that I have a problem with. So my idea is that if f is 9 times its original size, then because we are dealing with area the k is 2. which means that 9=x^2. which would make my answer 3. Right?
Click here to see answer by edjones(3292)  |
Question 110865: Half life question. Please help if possible.
The half-life of the radioactive element plutonium-239 is 25,000 years. If 16 grams of plutonium-239 are initially present, how many grams are present after 25,000 years? 50,000 years? 75,000 years? 100,000 years? 125,000 years?
Click here to see answer by ankor@dixie-net.com(6691)  |
Question 110978: A radioactive element sodium-24 has a half-life of 14 hours and is used to help locate obstructions in blood flow. A procedure requires 1.5 grams and is scheduled to take place in 37 hours.
At what rate is the sodium-24 decaying?
What is the minimum amount of sodium-24 that must be on hand now?
Click here to see answer by stanbon(26259)  |
Question 113524: Dutch settlers purchased Manhattan Island from the Manhattan Indians for $24. If the Indians had deposited that money into a bank at 5% intrenst compunded quarteyly what would the account be worth today?
do th e problem again assuming the money was deposited continuously for the same amount of time.
I have no idea what to do for this probelem. I know that for the first part I have to use the compund intrest formula which is A=P(1+r/n)^nt, and for the second part I have to use A=Pe^rt. From here I'm lost please help.
Thanks
Click here to see answer by stanbon(26259) |
Question 113540This question is from textbook Glencoe Algebra 2
: A radioisotope is used as a power source for a satellite. The power output is given by the equation P=50e^-t/250, where P is the power in watts and t is the time in days.
a). Find the power available after 100 days
b). Ten watts of power are required to operate the equipment in the satellite. How long can the satellite continue to operate?This question is from textbook Glencoe Algebra 2
Click here to see answer by stanbon(26259) |
Question 113772: x^0.40=0.263407446 Solve for x.
I know this problem looks weird but i am a college physics student and i was able to simplify it this far but i dont know how to solve for x fom this point.
i have already taken Calculus I at the college level and all math courses preceding it but i have never ran into a problem quite like this. Please help me.
Click here to see answer by checkley71(8405) |
Question 113754: with the compound interest formula:
A=amount, P=principle, r=annual interest rate, n=# of times it is compounded per year, and t=# of years so that: A=P(1+ r/n)^nt, find the length of time it takes for the investment to increase M fold (M=2 double, M=3 triple), for time in terms of M,r,and n
Click here to see answer by josmiceli(3003) |
Question 113533This question is from textbook Glencoe Algebra 2
: The intensity of light decreases as it passes through sea water. The equation ln Io/I= 0.014d relates the intensity of light I at the depth of d centimeters with the intensity of light Io in the atmosphere. Find the depth of the water where the intensity of the light is half the intensity of the light in the atmosphere.
Thanks for your help.This question is from textbook Glencoe Algebra 2
Click here to see answer by scott8148(3382) |
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