SOLUTION: log2 (2x-1)=log4 (3x^2-4x+2)

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Question 991939: log2 (2x-1)=log4 (3x^2-4x+2)
Found 2 solutions by MathLover1, MathTherapy:
Answer by MathLover1(20850)   (Show Source): You can put this solution on YOUR website!

......change to base ten


....cross multiply


........if log same, we have
......solve for




solutions:
=>
=>....disregard negative solution,
so, your solution is



Answer by MathTherapy(10555)   (Show Source): You can put this solution on YOUR website!

log2 (2x-1)=log4 (3x^2-4x+2)


 ----- Changing base on right side to base 10

 ------- Changing base on right side to base 2



 ----- Cross-multiplying











(x - 1)(x + 1) = 0

		OR           x  = - 1 (ignore) 

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