SOLUTION: I'm having trouble solving for 'x' in the equation {{{1.5(1.05)^x = 2(1.01)^x}}} I have tried turning it into a log, so I can solve for the approximate answer on a calculator, but
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Question 98613This question is from textbook Calculus with Applications Brief Version
: I'm having trouble solving for 'x' in the equation I have tried turning it into a log, so I can solve for the approximate answer on a calculator, but I can't figure out how to get the 'x' out of the exponent on each side. Can you help me?
This question is from textbook Calculus with Applications Brief Version
Found 2 solutions by Nate, stanbon:
Answer by Nate(3500) (Show Source): You can put this solution on YOUR website!
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Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
1.5(1.05)^x = 2(1.01)^x
Divide both sides by 1.5 to get:
(1.05)^x = (4/3)(1.01)^x
Divide both sides by (1.01)^x to get:
[(1.05)/(1.01)]^x = (4/3)
[1.03960...]^x = (4/3)
Take the log of both sides to get:
xlog [......._] = log(4/3)
x = log(4/3)/log[....]
x = 0.120179....
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Cheers,
Stan H.
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