SOLUTION: Find the equation of the tangent line to y=e^(-9t) at t=0 I already used t=0 to find a point- f(0)=e^(-9x0)= 1 so my point is at (0,1) but I'm unsure of what to do next. Any help

Question 973603: Find the equation of the tangent line to y=e^(-9t) at t=0
I already used t=0 to find a point- f(0)=e^(-9x0)= 1 so my point is at (0,1) but I'm unsure of what to do next. Any help is appreciated thank you!
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
The slope of the tangent line at a point is equal to the value of the derivative at that point.
The derivative of f is,

So the value at is,

So then using the point-slope form of a line,

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