SOLUTION: How do you do this decay problem?
The radioactive isotope 123I, used in nuclear imaging, decays continuously at a rate of 5.25% per hour.
(a) Approximate the percentage remaini
Algebra.Com
Question 973066: How do you do this decay problem?
The radioactive isotope 123I, used in nuclear imaging, decays continuously at a rate of 5.25% per hour.
(a) Approximate the percentage remaining of any initial amount after 26.4 hours.
(b) What is the half-life of 123I?
For part a I think the formula for that is A(t)=A*e^(kt). The problem that I'm having with this is that I don't know the initial amount (A). Here are the variables:
A=?
k=?
t=26.4
It seems like it's asking what (k) would be but I don't know how to solve for (k) without knowing the initial amount (A). I think I may be looking at it wrong. Any help on this one would be appreciated. I know how to do part b but I need to know how to do part a first before I can do b.
Thank you!!
Answer by josgarithmetic(39620) (Show Source): You can put this solution on YOUR website!
Retention is percent each hour.
Starting with quantity 1, Using the model,
and the model is more specifically .
HALF-LIFE
hours
RELATED QUESTIONS
The Radioactive isotope technetium 99m (99mTc) is used in imaging the brain. the isotope... (answered by htmentor)
The radioactive isotope technetium 99m is used in imaging the brain. The isotope has a... (answered by greenestamps)
How do I solve this growth and decay problem it reads: A material decays at a rate of... (answered by josgarithmetic)
How do I solve this growth and decay problem it reads: A material decays at a rate of... (answered by josgarithmetic)
A certain radioactive isotope decays at a rate of 0.1% annually. Determine the half-life... (answered by stanbon)
A certain radioactive isotope decays at a rate of 0.1% annually. Determine the half-life (answered by ewatrrr)
Radioactive strontium-90 is used in nuclear reactors and decays exponentially with an... (answered by ankor@dixie-net.com)
A certain radioactive isotope decays at a rate of 1% per year; 3.4 kilograms of this... (answered by stanbon)
Solve the problem.
Use the formula N = Iekt, where N is the number of items in terms... (answered by ankor@dixie-net.com)