SOLUTION: Please help me am struggling with logarithms: 1log5^x=log5^(x-1)

SOLUTION: Please help me am struggling with logarithms: 1log5^x=log5^(x-1)

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Question 971197: Please help me am struggling with logarithms: 1log5^x=log5^(x-1)
Answer by josgarithmetic(39621) (Show Source): You can put this solution on YOUR website!
The expression within each log function would be equal:

and here, the exponents would be equal because each member uses the same base.

and that is impossible.
NO SOLUTION
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