SOLUTION: So how would I solve the equation: log2x+logx=11 for x? I'm stuck on this one, thanks!

Algebra.Com
Question 950860: So how would I solve the equation: log2x+logx=11 for x?
I'm stuck on this one, thanks!

Answer by lwsshak3(11628)   (Show Source): You can put this solution on YOUR website!
So how would I solve the equation:
log2x+logx=11 for x?
log(2x*x)=11
log(2x^2)=11
10^11=2x^2
x^2=(10^11)/2
x=±=±(10^5√10)/2

RELATED QUESTIONS

how do you do lgarithmic properties to solve an equation this is what i have... (answered by lwsshak3)
How do I complete this problem? For the exponential function ex and logarithmic function... (answered by josmiceli)
I am asked to solve the equation log(x)=log2x^2-2 would I have to get rid of log is so... (answered by Alan3354)
Logx-log16=log2x + logx Solve for x (answered by josmiceli,Boreal)
How do I solve the equation {{{ log2x=4-3logx2 }}}... (answered by josmiceli,stanbon)
I am stuck on an equation that I need to solve for inverse operations n over 2= -15... (answered by checkley77)
hi how are you doing today? well im stuck on this one promblem. the directions say, "Find (answered by prince_abubu)
(logx/log2x)=(log4x/log8x) solve for... (answered by stanbon)
How do I solve graphically for x and y? The equation is 3x-y=-4 and 2x-3y=9. How would it (answered by stanbon)