SOLUTION: For all values of "x" greater than 3, show how the equation: square root of x+9 equals x-3 is equivalent to x = x squared minus 6x (I do not know how to type the square root sign n

Question 945827: For all values of "x" greater than 3, show how the equation: square root of x+9 equals x-3 is equivalent to x = x squared minus 6x (I do not know how to type the square root sign nor the exponent i.e. squared)
Answer by rothauserc(4718) (Show Source): You can put this solution on YOUR website!
we are asked to show equivalence between two equations
1) (x+9)^(1/2) = x - 3
square both sides of =
x+9 = x^2 -6x +9
subtract 9 from both sides of =
x = x^2 -6x
divide both sides of = by x, we can do this because we are given that x not = 0
1 = x -6
x = 7
2) x = x^2 - 6x
divide both sides of = by x, we can do this because we are given that x not = 0
1 = x -6
x = 7
equations 1 and 2 have the same solution, they are equivalent

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