SOLUTION: Which of the following expressions is equivalent to 0.5(log(2)(x+1)-log(2)(x^2+2x+1)), where x can not equal -1? 2 = base of the logarithm
a. log(2)sqrt(1/x+1)
b. log(2)sqrt(
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Question 944210: Which of the following expressions is equivalent to 0.5(log(2)(x+1)-log(2)(x^2+2x+1)), where x can not equal -1? 2 = base of the logarithm
a. log(2)sqrt(1/x+1)
b. log(2)sqrt(x+1)
c. log(2)((x^2+2x+1)(x+1))
d. -3log(2)x
How do I go about solving a question like this, trying to find examples but I am struggling to find any, if someone could give me a step by step breakdown that would be greatly appreciated.
Thank you
Found 2 solutions by stanbon, Alan3354:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Which of the following expressions is equivalent to 0.5(log(2)(x+1)-log(2)(x^2+2x+1)), where x can not equal -1? 2 = base of the logarithm
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0.5(log(2)(x+1)-log(2)(x^2+2x+1)
= 0.5[log2[(x+1)/(x^2+2x+1)]]
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= 0.5[log2[(x+1)/(x+1)^2]]
----
= 0.5[log2[1/(x+1)]]
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= log2[sqrt[1/(x+1)]]
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Cheers,
Stan H.
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a. log(2)sqrt(1/x+1)
b. log(2)sqrt(x+1)
c. log(2)((x^2+2x+1)(x+1))
d. -3log(2)x
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
0.5(log(2)(x+1)-log(2)(x^2+2x+1))
=
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=
Subtracting logs --> division
=
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=
=
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Same as choice a.
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