SOLUTION: how do you find the inverse of a logarithm function my problem question is y=4log3(x)+1 the base or small number in the log function is 3 i know you have to substitute x for y

Question 936473: how do you find the inverse of a logarithm function
my problem question is y=4log3(x)+1
the base or small number in the log function is 3
i know you have to substitute x for y when you are doing the inverse and i got to the step x= 4log3(y)+1 but i am stuck on what to do after you substitute it.
Found 2 solutions by ankor@dixie-net.com, stanbon:
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
find the inverse of a logarithm function
my problem question is y=4log3(x)+1
Starting with what you have

Write the exponent equiv of logs

find the 4th root of both sides

; exponent is
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
find the inverse of a logarithm function
my problem question is y=4log3(x)+1
-----
Interchange x and y to get:
4log3(y)+1 = x
-----
Solve for "y"::
log3(y^4) = x-1
-----
y^4 = 3^(x-1)
----
y = 3^[(x-1)/4]
-----------------------
Cheers,
Stan H.
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