SOLUTION: 1. log2(x-3)=3-log2(x-1) (the base is log 2) 2. 6log7(x^2-1)-5log7(x-1) (the base is log 7) For the first problem i need to solve it and for the 2nd problem i need to express

Algebra.Com
Question 928299: 1. log2(x-3)=3-log2(x-1) (the base is log 2)
2. 6log7(x^2-1)-5log7(x-1) (the base is log 7)
For the first problem i need to solve it
and for the 2nd problem i need to express it as a single logarithm.
I have been trying to solve this but I am always off on my answers. I need to know how it is solve step by step. Thank you so much.

Answer by MathLover1(20849)   (Show Source): You can put this solution on YOUR website!
1. solve it



...in base



...if log. same, then
is same too; so, solve it for



...group



solutions:
if => ...your answer
if => ...reject negative value for log

2. express it as a single logarithm




....since , we will have







RELATED QUESTIONS

How would I solve this? log2(x-3)-log2(2x+1)=log24 (log base 2,... (answered by jsmallt9)
I need help figuring out which way to proceed to solve this problem. log2(x-2) +5 = 8-... (answered by Earlsdon)
Solve the equation for x. 3=log base of 2 number x Log2... (answered by stanbon)
solve for x: log 2 (x-1) - log 2 (x+2) + log2 (x+3) = 2 (answered by ikleyn,MathLover1)
Solve for x: log2 8 1/3-2x *note: the "2" after "log" is a subset, or "little"... (answered by stanbon)
solve for log(3x-1) + log2= log4 +... (answered by lwsshak3)
Log[log(2+log2(x+1))]=0 (answered by Alan3354)
What is the value 3+log(base)2 (x) = log(base 2)... (answered by lwsshak3)
How do I solve the following logarithm for x? The base of the following logs is 2.... (answered by stanbon,MathLover1)