SOLUTION: I am so bad with these can someone help me solve this problem: x = log7(1/49) The 7 is slightly below the log not beside it. I hope that helps.

Question 91336: I am so bad with these can someone help me solve this problem:
x = log7(1/49)
The 7 is slightly below the log not beside it. I hope that helps.
Answer by tutor_paul(519) (Show Source): You can put this solution on YOUR website!
x = log7(1/49)
==============
Think of a logarithm in terms of what it means in exponent form.
The "7" is the base, the "1/49" is the answer, and the logarithm is the exponent. In other words, you problem can be re-written as:

When written in this form, you can easily see that

That is your answer.
Good luck,
tutor_paul@yahoo.com

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