SOLUTION: log (x-4) = log 32 - log x log (x+1) + 2*log (x) = log (x^2+8)

Question 885046: log (x-4) = log 32 - log x
log (x+1) + 2*log (x) = log (x^2+8)
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!

Answer by MathTherapy(10552) (Show Source): You can put this solution on YOUR website!
log (x-4) = log 32 - log x
log (x+1) + 2*log (x) = log (x^2+8)

log (x-4) = log 32 - log x
Simplifies to: (x - 8)(x + 4) = 0
OR x = - 4 (ignore)
log (x+1) + 2*log (x) = log (x^2+8)
Simplifies to:

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