SOLUTION: Could someone help me with this problem? log(x^2+6) - log(x+1) = 2 + log(x-1) The book says that the answer is the sqrt (106/99) or approximately 1.03 I need to know the s

Question 878789: Could someone help me with this problem?
log(x^2+6) - log(x+1) = 2 + log(x-1)
The book says that the answer is the sqrt (106/99) or approximately 1.03
I need to know the steps in completing this problems so I can learn how to do it for the test.
Thank you.
Answer by josgarithmetic(39618) (Show Source): You can put this solution on YOUR website!
log(x^2+6) - log(x+1) = 2 + log(x-1)
log(x^2+6)-log(x+1)-log(x-1)=2
log(x^2+6)-(log((x+1)(x-1))=2
log((x^2+6)/((x+1)(x-1))=2
Assuming the base is 10, the exponential form is

Is that enough for you to continue and finish?
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