SOLUTION: 1: 2 log7(x+1)=2
2: log3(2x+1)+ log3(x+4)-2
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Question 868026: 1: 2 log7(x+1)=2
2: log3(2x+1)+ log3(x+4)-2
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
1: (x+1)^2 = 49,
x^2 - 2x + 1 - 49 = 0,
x^2-2x-48 = 0
(x-8)(x+6) = 0, x = 8 (-6 an extraneous root)
2: (2x+1)(x+4) = 9
2x^2 + 9x -5 = 0
(2x - 1)(x+5)= 0, x = 1/2 (-5 an extraneous root)
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