SOLUTION: An amount of $1000 is invested and interest is compounded continuously. Find the annual relative growth rate for the investment to grow to $2500 in 10 years. Solve algebraically.

Question 863621: An amount of $1000 is invested and interest is compounded continuously. Find the annual relative growth rate for the investment to grow to $2500 in 10 years. Solve algebraically.
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!

 

Hi,

A = Pe^(rt)



ln(2.5)/10 = r = 9.16% 

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