SOLUTION: find x
1) log (x-1) to base 2 + log (x+1) to base 2 = 3
2) log (4-2x)=log(x+1)
3) log (9-2x) to base 1/3=log1/3(x-6)
thank you so much!
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Question 829853: find x
1) log (x-1) to base 2 + log (x+1) to base 2 = 3
2) log (4-2x)=log(x+1)
3) log (9-2x) to base 1/3=log1/3(x-6)
thank you so much!
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
find x
1) log (x-1) to base 2 + log (x+1) to base 2 = 3
x = 3
----
x = -3 is rejected, gives log(-4)
===================================
2) log (4-2x)=log(x+1)
Simple
=============
3) log (9-2x) to base 1/3=log1/3(x-6)
Is 1/3 the base of both?
Use log(1/3,(9-2x)) with 3 sets of braces { } to render legibly.
Click "Show source" to see the format.
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