SOLUTION: If I had the equation, 60.6=58e^-k(1), how would I solve it using Newton's Law of Cooling? I am clueless when it comes to Newton's Law of Cooling, so could you please explain that

Question 81826: If I had the equation, 60.6=58e^-k(1), how would I solve it using Newton's Law of Cooling? I am clueless when it comes to Newton's Law of Cooling, so could you please explain that to me as well. Thank you in advance.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
60.6=58e^-k(1), how would I solve it using Newton's Law of Cooling?
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There is only one variable, k, so that is what you are solving for.
1.044828 = e^(-k)
Take the natural log of both sides to get;
-k = 0.043852
k= 0.043852
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As for Newton's Law of Cooling, I suggest you use Google
to find a readable explanation.
==================
Cheers,
Stan H.
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