SOLUTION: Hello: Here is my problem that I need assistance with. Thank you. The period T (in seconds) of a simple pendulum is a function of its length L (in feet), given by T(L) = 2 p

Question 81536This question is from textbook Coll. Algebra
: Hello:
Here is my problem that I need assistance with. Thank you.
The period T (in seconds) of a simple pendulum is a function of its length L (in feet), given by T(L) = 2 pi square root of L/G where G = 32.2 feet per second. Per second is the acceleration of gravity. Express length L as a function of the period T. This question is from textbook Coll. Algebra

Answer by tutor_paul(519) (Show Source): You can put this solution on YOUR website!

The problem is asking you to solve for L in terms of T.
First get the square root term alone on one side of the equation:

Square both sides to get rid of that square root:

Solve for L:

Good Luck,
tutor_paul@yahoo.com
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