SOLUTION: I have to solve this problem:
2+6e(4x)=19 (the 4x is the exponent)
I have come up with these possible answers:
.2604, .5074, .4907, or 2.8333
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Question 81497This question is from textbook Glencoe Mathmatics Algebra 2
: I have to solve this problem:
2+6e(4x)=19 (the 4x is the exponent)
I have come up with these possible answers:
.2604, .5074, .4907, or 2.8333
This question is from textbook Glencoe Mathmatics Algebra 2
Answer by rapaljer(4671) (Show Source): You can put this solution on YOUR website!
This is a classic problem of "undo-ing" the operations of math in order to solve for x.
2+6e(4x)=19
First, you need to "undo" the 2 that is added to the term that contains the x. Of course, you do this by subtracting 2 from each side of the equation:
Next, you must "undo" the 6 that is multiplied times the term containing the x:
Next, you must "undo" the "e" raised to the power. The inverse of "e" raised to the power is the "ln" function, so you must take the "ln" of each side:
Finally, undo multiplication of the x times 4 by either dividing both sides by 4 or by multiplying both sides times .
Final answer
R^2 at SCC
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