SOLUTION: I need help with this problem plzz!! Solve the following equation exactly: log(x+1)+log2=1

Algebra.Com
Question 811242: I need help with this problem plzz!!
Solve the following equation exactly: log(x+1)+log2=1

Answer by mananth(16946)   (Show Source): You can put this solution on YOUR website!
log(x+1)+log2=1
log(x+1)+log2=log10
log(2(x+1))=log10
2(x+1)=10
2x+2=10
2x=8
x=4

RELATED QUESTIONS

I need help solving the following... (answered by stanbon)
I need help with solving this logarithmic equation log... (answered by jim_thompson5910)
Hi again, I could use some help with this problem: Solve the logarithmic equation:... (answered by Nate)
I need help solving for x in the following equation log(x+3) + log(x-1) = log... (answered by Theo)
This is the equation which i have and I dont know how to solve it:... (answered by jsmallt9)
1. log2(x-3)=3-log2(x-1) (the base is log 2) 2. 6log7(x^2-1)-5log7(x-1) (the base is... (answered by MathLover1)
I need help with this problem:... (answered by nerdybill)
How would I solve this? log2(x-3)-log2(2x+1)=log24 (log base 2,... (answered by jsmallt9)
I need help with this problem? Use the Quadratic Formula to solve the equation.... (answered by solver91311)