SOLUTION: 8(c3 - c) = c (6c + 1) or 8(c^3-c) = c (6c+1)

Question 80737: 8(c3 - c) = c (6c + 1)
or
8(c^3-c) = c (6c+1)
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!

Distribute

Get all terms to one side

Combine like terms

Factor out a c

Now factor
note: this solver uses x instead of c
ERROR Algebra::Solver::Engine::invoke_solver_noengine: solver not defined for name 'quadratic_factoring'.

Error occurred executing solver 'quadratic_factoring' .

So we have

which gives us

or or Set each individual factor equal to zero

or or Now solve for c in each case

So our answer is

or or
RELATED QUESTIONS
16: 8(c3 - c) = c (6c + 1) (answered by checkley75)

16: 8(c^3 - c) = c (6c +... (answered by stanbon)

(6c)^3/c Is the answer... (answered by Alan3354)

1/18c - 1/36 + 1/6c = 1/6 + c (answered by rfer)

... (answered by stanbon)

-5(-c+d)+6c-4d (answered by xcentaur)

Factor:... (answered by ilana)

factor;... (answered by MathLover1)

3/(4c+2)-(c-4)/(2c^2+c)-5/6c (answered by rmromero)