SOLUTION: (Root of 256)^(2x +3) = (1/64)^(x-5) (256^1/2)^(2x+3)=(1/64)^(x-5) (256)^(x+1/2)

Question 804477: (Root of 256)^(2x +3) = (1/64)^(x-5)
(256^1/2)^(2x+3)=(1/64)^(x-5)
(256)^(x+1/2)
Found 2 solutions by stanbon, erica65404:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
(Root of 256)^(2x +3) = (1/64)^(x-5)
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(sqrt(2^8))^(2x+3) = (2^-6)^(x-5)
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(2^4)^(2x+3) = 2^(30-6x)
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2^(8x+12) = 2^(30-6x)
----
8x+12 = 30-6x
14x = 8
x = 4/7
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Cheers,
Stan H.
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Answer by erica65404(394) (Show Source): You can put this solution on YOUR website!

log both sides

x=1.29
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