SOLUTION: solve using natural logs 2^(x/2) = 5 I think it would be 2ln(5)/ln(2). Is that correct? If not how do you solve it?

Question 799861: solve using natural logs
2^(x/2) = 5
I think it would be 2ln(5)/ln(2). Is that correct? If not how do you solve it?
Answer by DrBeeee(684) (Show Source): You can put this solution on YOUR website!
You are correct.
Given:
(1) 2^(x/2)= 5
Take the ln of each side to get
(2) (x/2)ln(2) = ln(5) or
(3) xln(2) = 2ln(5) or
(4) x = 2ln(5)/ln(2)
Since
(5) 2ln(5) = ln(5)^2 or
(6) 2ln(5) = ln(25)
We may also write (4) as
(7) x = ln(25)/ln(2)
RELATED QUESTIONS
How would you solve for "x" if... ln(x^2-16)=... (answered by ewatrrr)

Log rules question ln((a^2)/(b^2)(c^1/2)) if I were to use log rules on this what... (answered by josgarithmetic)

I think I have to solve it using the log functions not sure the problem reads... solve... (answered by Edwin McCravy,ankor@dixie-net.com)

2ln(X-3)= ln(X+5) + ln4 I have natural logarithms so think can use the one to one... (answered by jim_thompson5910)

f(x) = ln (x-e)-1 how do i sketch the graph and find the domain? i really don't... (answered by jsmallt9)

8 * 2^x = 3^x solve using natural logs (answered by tommyt3rd)

Solve for x using logs. 2^x=e^(x+5) I know im supposed to use ln, but I get stuck... (answered by John10)

how do I solve... (answered by stanbon)

solve ln x-2ln 3=2 (answered by stanbon)