SOLUTION: These questions confuse me a bit and this site has helped me before. Thank you, please show me how to solve these problems (for x) .
16) log(x+4)-log6=1
18) log(x-1)^2=log(-5x-1)
Algebra.Com
Question 748655: These questions confuse me a bit and this site has helped me before. Thank you, please show me how to solve these problems (for x) .
16) log(x+4)-log6=1
18) log(x-1)^2=log(-5x-1)
please help. thank you again so much.
Found 2 solutions by stanbon, MathTherapy:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
log(x+4)-log6=1
log[(x+4)/6] = 1
(x+4)/6 = 10^1
x+4 = 60
x = 56
----------------------------
18) log(x-1)^2=log(-5x-1)
(x-1)^2 = -5x-1
x^2 -2x + 1 = -5x -1
-----
x^2 +3x = 0
x(x+3) = 0
x = 0 or x = -3
------------------
Cheers,
Stan H.
Answer by MathTherapy(10556) (Show Source): You can put this solution on YOUR website!
please show me how to solve these problems (for x) .
16) log(x+4)-log6=1
18) log(x-1)^2=log(-5x-1)
please help. thank you again so much.
16) log(x+4)-log6=1
x + 4 = 60 ------- Cross-multiplying
x = 60 - 4, or
18) log(x-1)^2=log(-5x-1)
(x + 1)(x + 2) = 0
, or
You can do the check on both!!
Send comments and “thank-yous” to “D” at MathMadEzy@aol.com
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