SOLUTION: How do you solve -16+0.2(10)^x=35

Algebra.Com
Question 74757: How do you solve -16+0.2(10)^x=35
Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!

Add 16 to both sides

Divide both sides by 0.2
Take the log of both sides, this undoes the base 10 to the unknown exponent



Check:
Plug in




These two are really close to being equal. They would be if not for decimal roundoff error, so it works.

RELATED QUESTIONS

how do you solve?... (answered by jim_thompson5910)
how do you solve?... (answered by jim_thompson5910)
How do you solve this quadratic equation? x^2 − 16 =... (answered by richwmiller)
how do you solve the following equation?... (answered by lynnlo)
how do you solve 6x^2-11x-35=0 (answered by jim_thompson5910)
How do you solve this equation ? {{{ 5n^2 +35 = 0... (answered by Alan3354)
How do you solve... (answered by jim_thompson5910)
how do you solve x-2/4=... (answered by lwsshak3)
how do you solve log6x+ log6 (x+16)= 2... (answered by solver91311)