SOLUTION: Please help me solve this equation. I am having trouble finding all the steps. log(16+2x)=log(x^2-4x)

Question 746193: Please help me solve this equation. I am having trouble finding all the steps.
log(16+2x)=log(x^2-4x)
Found 2 solutions by josgarithmetic, savvyhush23:
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
You read that as, in a more general way, the logarithm of this expression equals the logarithm of that expression. So we must expect that "this" expression is equal to "that" expression. There is a way to make this much more formal, but doing so should be unnecessary.

No steps to get confused, unless you are unfamiliar with quadratic equations.
Answer by savvyhush23(50) (Show Source): You can put this solution on YOUR website!
Please help me solve this equation. I am having trouble finding all the steps.
log(16+2x)=log(x^2-4x)
.
.
Is it finding x value in order for the function to be equal?
.
.
If that so, since both side is in logarithm, you can eliminate log leaving:
move 16 + 2x to the right,

the function is a quadratic equation, therefore to find x, use quadratic formula:
a = 1, b = -6 and c = -16

.
.
Therefore the answer are 8 and -2

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