SOLUTION: 16^(x+4)=8^(3x-2)
Algebra.Com
Question 745491: 16^(x+4)=8^(3x-2)
Answer by tommyt3rd(5050) (Show Source): You can put this solution on YOUR website!
For this example our strategy is to make the bases equal, then we can set the exponents equal:
so x=22/5
RELATED QUESTIONS
16^2-x=8^3x (answered by ewatrrr)
16^x=4^3x-2 (answered by edjones)
Solve 2+x/2+3x/8=16
(answered by CubeyThePenguin)
4(x-8)^2=16 (answered by tommyt3rd)
{{{ 1/(x+4) + 3/(x-4) = (3x+8)/(x^2-16)... (answered by stanbon)
(8 ) (3x+15)
____________*_________
(x^2-25) *... (answered by edjones)
3x-x+8=16
(answered by checkley71)
(-3x^2+16)-(x^2+22x+4) (answered by Boreal)
3x/2 +... (answered by drk)