SOLUTION: log base 7 (x+4) - log base 7 (x) = 2
How would I solve this?
{{{log(7,(x+4))-log(7,x)=2}}}
Algebra.Com
Question 719786: log base 7 (x+4) - log base 7 (x) = 2
How would I solve this?
Answer by josgarithmetic(39623) (Show Source): You can put this solution on YOUR website!
Your key to begin is , and .
Translate into exponential form:
RELATED QUESTIONS
Log base 2 (4)log base 2 (x) + log base 2 (7) =3
(answered by Fombitz,MathTherapy)
log base4 (x^2 +7) +log base 4 8=5
(answered by Fombitz)
log base 16 of x + log base 4 of x + log base 2 of x = 7
solve for... (answered by lwsshak3)
Solve for x:
A.) Log(base 3)4 + log(base 3)5 = log(base 3)(4x+5)
B.)log(base 7)6... (answered by algebrapro18)
solve for x if log 4 base 2 + log 7 base 2 - log x base... (answered by lwsshak3)
how would you solve
log base 2(5x-1)- log base... (answered by Gogonati,ewatrrr)
solve for x:
log(of base 7)x = (1/2)log(of base 7)36-(4)log(of base... (answered by edjones)
2/log(base x)4 + 3/log(base 4)x =... (answered by lwsshak3)
log (base 7) 2 + log (base 49) x = log (base 1/7) sqrt... (answered by mathsnight)