SOLUTION: I need help with this homework question:
You are cooking chili. When you take it off the stove, it has a temperature of 205 degrees F. The room temperature is 68 degrees F and t
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Question 718211: I need help with this homework question:
You are cooking chili. When you take it off the stove, it has a temperature of 205 degrees F. The room temperature is 68 degrees F and the cooling rate is r=0.03 . How long will it take to cool to a serving temperature of 95 degrees F?
T= (T0 - TR)e^-rt + TR
T= cooling time in minutes
T0= initial temperature
TR= room temperature
r= cooling rate
I have the equation 95= (205 - 68)e^-.03t +68
I am just confused on how to solve for t and using logarithm/ natural long and the process for how to find t, etc. Thanks!
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
T= (T0 - TR)e^-rt + TR
T= cooling time in minutes
T0= initial temperature
TR= room temperature
r= cooling rate
given:
Take the natural log of both sides
The time is 54 min 8 sec
---------------------
If you have trouble with , say it in words
and it becomes clearer:
What is the log to the base that gives me as a result
? It must be .
Does this help?
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