SOLUTION: I need help. For the following problem I found no solution:
2log2 (x+6) - log2 16 = 2
heres my work:
log2 x^2+36-16 = 2
x^2+20 = 2^2
x^2+20 = 4
x^2=-16
then there is
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Question 71074: I need help. For the following problem I found no solution:
2log2 (x+6) - log2 16 = 2
heres my work:
log2 x^2+36-16 = 2
x^2+20 = 2^2
x^2+20 = 4
x^2=-16
then there is no real number for the square root of -16
Answer by checkley75(3666) (Show Source): You can put this solution on YOUR website!
True there is no real number root but there is a root!
x^2=-16
x=4i
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