SOLUTION: Solve log(base6) (x^2+7)=log(base6)(1-5x)

Question 696959: Solve log(base6) (x^2+7)=log(base6)(1-5x)
Found 2 solutions by lwsshak3, MathLover1:
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Solve log(base6) (x^2+7)=log(base6)(1-5x)
x^2+7=1-5x
x^2+5x+6=0
(x+3)(x+2)=0
x+3=0
x=-3
or
x+2=0
x=-2
Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!
...this will be equal for

...now find solutions for

.....use quadratic formula

...enter , , and

solutions:

or

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