SOLUTION: Let E(x) = 30(1.05)^x and L(x) = 30 + 2x. I need to give an example of a value x when L(x) < E(x). Can someone please help? I am really struggling with this one. I have the res

Question 695850: Let E(x) = 30(1.05)^x and L(x) = 30 + 2x.

I need to give an example of a value x when L(x) < E(x). Can someone please help? I am really struggling with this one. I have the rest of the problem figured out.
Answer by KMST(5328) (Show Source): You can put this solution on YOUR website!
is a cleverly named inear function, while
is a cleverly named xponential function.

Linear functions graph as straight lines, and represents a line with a slope of throughout its all real numbers domain.

Exponential functions graph as curved lines, and if the base is greater than one, as for , have "exponential growth" graphs that look like this , with slopes that increase from very small to very large.

The line could be tangent to the exponential curve and the graphs could intersect at only one point, as in
Otherwise, a linear curve and an exponential curve could intersect at two points , or zero points .

In any of those cases, the line is below the exponential curve () at most (if not all) points, for most (if not all) values of .

Which of those scenarios is the case for your functions?
and
, so the graphs intersect at a least one point, with .
We can look at points to either side.
If the curves are tangent at , for all other values of
it will be (.
If the curves are not tangent at , then they intersect at two points,
In that case, will be true at least in some interval to one side of , and we may be lucky enough to find a point there.

For :
and
so for ,

For :
and
=approx. so for ,

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