SOLUTION: 8-log^2 64 =? do you put the 8 as the exponent of 64 then divide the who thing by negative one to get rid of the negative in front of the log or should I subtract after

Question 694141: 8-log^2 64 =? do you put the 8 as the exponent of 64 then divide the who thing by negative one to get rid of the negative in front of the log or should I subtract after
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Since the poswer of 2 that gives 64 is 6
log2(64) = 6
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8-log^2 64 =?
----
8 - 6
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= 2
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Cheers,
Stan H
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