SOLUTION: how do you solve these equations 1) e^-x=5 2) 11^5x=33 3) 4e^2x=17

Algebra.Com
Question 694003: how do you solve these equations
1) e^-x=5
2) 11^5x=33
3) 4e^2x=17

Answer by lwsshak3(11628)   (Show Source): You can put this solution on YOUR website!
how do you solve these equations
1) e^-x=5
-xlne=ln5
x=-ln5
..
2) 11^5x=33
5xlog11=log33
5x=log33/log11
x=(log33/log11)/5
x≈0.2916
..
3) 4e^2x=17
ln4+2xlne=ln17
2x=ln17-ln4
x=(ln17-ln4)/2
x≈.7235

RELATED QUESTIONS

How do you solve these algebraically: 1) log(x+1)+log(x-1)=log(3) 2)... (answered by Earlsdon)
How do i solve... (answered by Alan3354)
How do i solve... (answered by lynnlo)
Solve for x: e^2x + 4e^-2x = 4. X= a. (1/2) ln 2 b. (1/3) ln 2 c. (1/3) ln 3 d.... (answered by stanbon,venugopalramana)
How do I solve these equations? 1/2x=1/5x+5/2... (answered by stanbon)
1.) e^x=148.413 2.) 25=e^3x 3.) 9e^5x=5 4.) 1/4e^x=30 (answered by lwsshak3)
Solve for x 4e^2x-3 =... (answered by ReadingBoosters)
4e^x+2=32 ln(5x-3)^1/3=2 2x^(3x-2)+4=16 2e^(x-2)=e^x+7 1/3lnx+ln2-ln3=3... (answered by ankor@dixie-net.com)
How do you solve these matrices equations? 

1. -3x +[7  0  -1] = [10     0   8]
  (answered by Edwin McCravy)