SOLUTION: 3log2 x=1+log2 32

SOLUTION: 3log2 x=1+log2 32

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Question 67909: 3log2 x=1+log2 32
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
3log2 x=1+log2 32
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log(base2)x^3 = 1+log(base2)32
log(base2)[x^3/32] = 1
x^3/32 = 2^1
x^3=64
x=4
Cheers,
Stan H.
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