SOLUTION: How do I solve the equation 4^2X=64? The teacher gave us the answer, 3/2, but I don't know the steps to get to that answer.
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Question 673067: How do I solve the equation 4^2X=64? The teacher gave us the answer, 3/2, but I don't know the steps to get to that answer.
Found 3 solutions by mananth, Alan3354, MathLover1:
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
4^2X=64
2x log 4 = log 64
2x= log 64/log4
2x=3
x= 3/2
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
How do I solve the equation 4^2X=64? The teacher gave us the answer, 3/2, but I don't know the steps to get to that answer.
-----------
4x = 6
x = 3/2
That's one way.
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2x = 3, etc
==============
2x*log(4) = log(64)
x = 3/2
Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!
........if base same, exponents are same too; so, we have
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