SOLUTION: help me solve ln(x^2 + 12)=ln x + ln 8
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Question 67199This question is from textbook
: help me solve ln(x^2 + 12)=ln x + ln 8
This question is from textbook
Found 2 solutions by bam878s, funmath:
Answer by bam878s(77) (Show Source): You can put this solution on YOUR website!
This problem is simple once you utilize a common law of logarithms.
ln ab = ln a + ln b
On the right hand side of this equation we have ln x + ln 8. By using the above law, we can write this as ln 8x.
So, we have:
ln( + 12) = ln 8x. So now we know that + 12 = 8x
+ 12 = 8x
+ 12 - 8x = 0
- 8x + 12 = 0. We can solve this by using the quadratic formula, but an easier way would be to factor this out as follows:
- 8x + 12 = (x-6) * (x-2). So, we have:
(x-6)(x-2) = 0. We know that 0 * anything = 0, so now we can easily see that
x = 6 or x = 2.
Hope this helps!!
Answer by funmath(2933) (Show Source): You can put this solution on YOUR website!
Rules:
1.
2. If then
:
solve ln(x^2 + 12)=ln x + ln 8
rule 1
rule 2
set = to 0
Factor
x-2=0 or x-6=0
x-2+2=0+2 or x-6+6=0+6
x=2 or x=6
Check for extraneous solutions.
2.772588722=.6931471806+2.079441542
2.772588722=2.772588722 x=2 is valid
ln(48)=3.871201011
3.87201011=3.8712011 x=6 is valid, too.
or
Happy Calculating!!!
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