SOLUTION: the answer is {{{(4e^(2/3))/3e but i need work please help ln4x-ln3-2lnx=(1/3)

Question 64576: the answer is (4e^(2/3))/3e but i need work please help
ln4x-ln3-2lnx=(1/3)
Answer by venugopalramana(3286) (Show Source): You can put this solution on YOUR website!
the answer is the answer is (4e^(2/3))/3e but i need work please help
ln4x-ln3-2lnx=(1/3)
USE FORMULAE
LN(X/Y)=LN(X)-LN(Y)
LN(X)+LN(Y)=LN(XY)
A*LN(X)=LN(X^A)
AND IF
LN(X)=A
X=E^A
LN(4X)-LN(3)-2LN(X)= LN(4X/3)-LN(X^2)=LN[4X/3X^2)=LN[4/(3X)]=1/3
E^(1/3)=4/(3X)
X=(4/3)[E^(-1/3)]=4/{3*E^(1/3)}=[4E^(2/3)]/[3*{E^(1/3)}{E^(2/3)}]
=[4*E^(2/3)/(3E)]
RELATED QUESTIONS
Please show me how to work this problem i know the answer is (4e^(2/3))/3e... (answered by venugopalramana)

condense 6lnx-1-ln3. i got ln(x^6/3), but the answer says ln(x^6/3e). where did the e... (answered by venugopalramana)

4e^x+2=32 ln(5x-3)^1/3=2 2x^(3x-2)+4=16 2e^(x-2)=e^x+7 1/3lnx+ln2-ln3=3... (answered by ankor@dixie-net.com)

For what values of x is the following true? ln(2x+3) = 2lnx+ln3... (answered by stanbon)

i need the answers to these following questions. what is the solution of the equation?... (answered by Fombitz)

I need help with this problem:... (answered by RAY100)

can someone help me solve the equation e^2lnx +3e^ln2x... is it the same as x2+2x^3 and... (answered by Alan3354,solver91311)

I need help rewriting the expressions as a single logarithm. 1) 2lnx + 4lny 2)... (answered by Gogonati)

I need help with logs log3(x+1)=log3 6 is it like x+1/3 =... (answered by Alan3354)